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5x^2+220x-5000=0
a = 5; b = 220; c = -5000;
Δ = b2-4ac
Δ = 2202-4·5·(-5000)
Δ = 148400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{148400}=\sqrt{400*371}=\sqrt{400}*\sqrt{371}=20\sqrt{371}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(220)-20\sqrt{371}}{2*5}=\frac{-220-20\sqrt{371}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(220)+20\sqrt{371}}{2*5}=\frac{-220+20\sqrt{371}}{10} $
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